Two stationary positive point charges, charge 1 of magnitude 3.00 nC and charge 2 of magnitude 1.80 nC , are separated by a distance of 31.0 cm . An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed vfinal of the electron when it is 10.0 cm from charge 1?
Answers: 1
![V_1 = k [\frac{q_1}{\frac{d}{2} } + \frac{q_2}{\frac{d}{2} } ]](/tpl/images/0585/3829/22529.png)
for k (Coulomb constant ) , 
for 
, 
for 
and 31.0cm= 
for d ![V_1 = (9*10^9) [\frac{3.95*10^{-9} ]}{\frac{0.31}{2} } + \frac{1.80*10^{-9}}{\frac{0.31}{2} } ]](/tpl/images/0585/3829/d566b.png)
![V_2 = k [\frac{q_1}{d_1} + \frac{q_2}{d_2} ]](/tpl/images/0585/3829/ee665.png)
for 
, (31-10)cm = 
for 
and the rest of the values ![V_2 = (9*10^9) [\frac{3.95*10^{-9}}{0.10} + \frac{1.80 *0^{-9}}{0.21} ]](/tpl/images/0585/3829/98d05.png)
) 
for m (mass of electron) , 
for q (charge on an electron) , and making v the subject
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Two stationary positive point charges, charge 1 of magnitude 3.00 nC and charge 2 of magnitude 1.80...
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