The nuclear equation is incomplete. Superscript 1 Subscript 1 Baseline H + Superscript 15 Subscript 7 Baseline N yields blank + Superscript 4 Subscript 2 Baseline H e What particle completes the equation? Superscript 12 Subscript 6 Baseline M g Superscript 11 Subscript 5 Baseline B Superscript 11 Subscript 5 Baseline N a Superscript 12 Subscript 6 Baseline C

The missing species is carbon-12 .

The nuclear equation should be .

Explanation:

Let represent the mass number of the missing species, and let represent its atomic number.

.

For this question, there are three things to consider:

The sum of the mass numbers on the left-hand side of this reaction is: .

The sum of the mass number on the right-hand side (including that of the missing species) is .

These two numbers should be the same. In other words, . Therefore, the mass number of the missing species would be .

The sum of the atomic numbers on the left-hand side of this reaction is: .

The sum of the mass number on the right-hand side (including that of the missing species) is .

These two numbers should be the same. In other words, . Therefore, the mass number of the missing species would be .

The atomic number of the missing species is . Look up a modern periodic table. The element with atomic number

i would think klcio3