An object with a mass of 450. grams is dropped off a 706m cliff. What is the velocity of the rock right before it impacts the ground.

Correct  V = 118.83 m/s

Explanation:

Given:

m = 450 g = 0.45 kg  mass of the object

H = 706 m  the height of the cliff from which the object was dropped

V = ?  final velocity before object impact the ground

This movement is a free fall.

The velocity is calculated using the following formula:

V² = 2 · g · H   in calculating we will use g = 10 m/s²

V² = 2 · 10 · 706 = 14,120  ⇒ V = √14,120 = 118.83 m/s

V = 118.83 m/s

God is with you!!!

answer: decibel

explanation:

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.