A proton travels at right angles through a magnetic field of 0.025 Tesla's. If the magnitude of the magnetic force on the proton is 1.8x10^-14 Newton's, what is the velocity of the proton

Velocity of proton will be equal to 4500 m/sec

Explanation:

We have given that proton moves right angles through a magnetic field

So angle between magnetic field and velocity of proton is

Magnetic field B = 0.025 Tesla

Charge on proton

Magnetic force on the proton is given

Magnetic force on a moving charge particle is equal to

So

v = 4500 m/sec

So velocity of proton will be equal to 4500 m/sec

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow