A 60.0­kg skier starts from rest at the top of a ski slope of height 62.0 . Part A If frictional forces do −1.06×10 4 of work on her as she descends, how fast is she going at the bottom of the slope?

v = 29.35 m /s

Explanation:

potential energy at the height of 62m

= m g h , m is mass , g is acceleration due to gravity and h is height

= 60 x 9.8 x 62

= 36456 J

negative work done by friction = -10600 J

energy at the bottom = 36456 - 10600 = 25856 J

This energy will be in the form of kinetic energy . If v be velocity at the bottom

1/2 m v² = 25856

1/2 x 60 x v² = 25856

v = 29.35 m /s

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

cancer risk hope this