Figure 3
(b) The surface is tilted to an angle of 37 degrees from the horizontal, as shown above in Figure 3 The blocks are each given a push so that at the instant show
Other
they are
go de
1. Each block has a mass of 0.20 kg Calculate the magnitude of the net force exerted on the two block system at the instant shown above

  3.92 N (straight down)

  2.36 N (down, parallel to the plane)

Explanation:

The only force acting on the system is apparently that due to gravity. The mass of the system is the sum of the masses of the blocks, so is ...

  0.20 kg + 0.20 kg = 0.40 kg

The force due to gravity is given by ...

  F = ma = (0.40 kg)(9.8 m/s²) = 3.92 N . . . (straight down)

That force is acting straight down, so is at an angle with respect to the direction the blocks are constrained to move.

The force down the plane is (3.92 N)·sin(37°) ≈ 2.359 N . . . (down the plane)

_____

Comment on the answer

We have given two answers to the question, because in this frictionless system, the force acting normal to the plane of motion is irrelevant to the system dynamics. The question asked for the net force on the system, which is the force due to gravity, so we have given that magnitude also.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

vapour or gas assuming atmospheriv pressure