Amodel rocket is launched straight upward with an initial speed of 50.0 m/s. it accelerates with a constant upward acceleration of 2.00 m/s2 until its engines stop at an altitude of 150 m. solve the following questions:

(a) what can you say about the motion of the rocket after its engines stop?
(b) what is the maximum height reached by the rocket?
(c) how long after liftoff does the rocket reach its maximum height?
(d) how long is the rocket in the air?

Part a)

the rocket will decelerate due to gravity and its speed will start decreasing after that

Part b)

Part c)

Part d)

Explanation:

Part a)

When Engine stops then the acceleration of the rocket is only due to gravity

So the rocket will decelerate due to gravity and its speed will start decreasing after that

Part b)

final speed of the rocket just before its engine is stopped is given as

now after this rocket will move under gravity

so maximum height from ground is given as

Part c)

Time taken by the rocket to reach 150 m height is given as

Now after this time to reach the maximum height is given as

total time is given as

Part d)

Time taken by the rocket to drop back on the surface is given as

so total time in air

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6