If the pressure exerted on a 268 mL sample of hydrogen gas at a constant temperature is increased from 0.6 atm to 0.8 atm, what will be the final volume of the sample?

If you understand this could you please help me?

201 mL

Explanation:

Initial volume V1 = 268 mL

Initial pressure P1 = 0.6 atm

Final volume of the gas V2 = ?

Final pressure of the gas P2 = 0.8 atm

Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

0.6 atm x 268 mL = 0.8 atm x V2

160.8 atm mL = 0.8 atm x V2

V2 = (160.8 atm mL / 0.8 atm)

V2 = 201 mL

Thus, the final volume of the hydrogen gas will be 201 mL

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

an electric circuit