A cylinder with a movable piston contains 2.00 gg of helium, HeHe, at room temperature. More helium was added to the cylinder and the volume was adjusted so that the gas pressure remained the same. How many grams of helium were added to the cylinder if the volume was changed from 2.00 LL to 3.90 LL ? (The temperature was held constant.)

The grams of helium added is 1.9 g

Explanation:

According to the ideal gas expression and due pressure, volume and temperature are constant, we have that V/n = constant

The number of moles is:

The moles of He added is:

nHe = 0.975 - 0.5 = 0.475 moles

The mass of He added is

mHe = 0.475 * 4 = 1.9 g

the answer is neither ball has a charge.

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if they were positively and negatively charged, they will seek.

it doesn't. it was imagined up in the middle ages.