A fish (8 kg) is being yanked vertically upward out of the water and the fishing line breaks. If the line is rated to a maximum tension of 160 N (~ 35 lb test), then what was the minimum acceleration of the fish (in m/s2)

Explanation:

Given:

Mass of the fish, 8 kg

Tension of the line, F = 160 N

Tension of the line, F + normal force = 0

Normal force, Fn = Mass × acceleration

Acceleration = force/mass

= 160/8

= 20 m/s^2

Minimum acceleration = 20 m/s^2

think about the oscillation of the toy shown in the video. when the toy is at the highest point of its motion, its velocity is zero and its acceleration is negative.

the answer to this question is 60 n