A plane loaded with cargo travels 2000 miles at an average speed of 400 Miles per hour. On the return trip on the same route it travels at an average speed of 480 miles per hour. How much quicker was the return trip

The trip was 434mph quicker.

Explanation:

Time taken for case 1 = distance/ time = 2000/400= 5hrs

Time taken in case 2 = distance / time = 2000/480= 4.2hrs

Time taken for the entire journey = 5 + 4.2 = 9.2hrs

Total distance = 2000+ 2000= 4000miles

Total speed = total distance / total time

Total speed = 4000/9.2 =434.78mph

50 mins quicker

Explanation:

Given:-

- The destination journey was made at, v_i = 400 mph

- The return journey was made at, v_f = 480 mph

- The distance between the start and end points is d = 2000 miles

Find:-

How much quicker was the return trip

Solution:-

- The time taken for the destination journey (t_i) can be determined from speed-distance-time formula:

                            t_i = d / v_i

                            t_i = 2000 / 400

                            t_i = 5 hrs

- Similarly, time taken for the return journey (t_f) can be determined from speed-distance-time formula:

                            t_f = d / v_f

                            t_f = 2000 / 480

                            t_f = 4.1667 hrs

- The comparison between destination and return journey can be made:

                            t_i - t_f

                            5 - 4.1667

                            0.8333 hrs

                            50 mins

- The return journey was 50 mins quicker than destination journey.

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explanation:

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