A voltmeter with resistance RVRVR_V is connected across the terminals of a battery of emf EEEMF and internal resistance rrr. Find the potential difference VmeterVmeterV_meter measured by the voltmeter.

V = E - Ir

Explanation:

According to ohms law which states that the current I passing through a metallic conductor at constant temperature is directly proportional to the potential difference V across its ends. Mathematically,

V = IR... (1)

or E = IRt ... (2)

where;

V is the potential difference across the resistance R

E is the source voltage known as the electromotive force

I is the current

Rt is the effective resistance.

If a voltmeter with resistance Rohms is connected across emf E and internal resistance r, the external resistance and internal resistance will be in series with each other and their equivalent resistance Rt = R+r... (3)

Substituting equation 3 into equation 2 will give;

E = I(R+r)

E = IR+Ir ... (4)

Note that from equation 1, the potential difference V = IR

Substituting V = IR into equation 4 will result into;

E = V+Ir

V = E-Ir

The fore the potential difference V measured by the voltmeter is;

V = (E-Ir) meters

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y