Physics, 01.04.2020 21:30 smagallanes

To learn to apply the concept of current density and microscopic Ohm's law. A "gauge 8" jumper cable has a diameter d of 0.326 cm. The cable carries a current I of 30.0 A. The electric field E in the cable is 0.062 V/m. Below is a list of some common metals with their:

Answers: 1

Show answers

Answers

Answer from: nana55959

Resistivity = (1.726 × 10⁻⁸) Ωm

Comparing this answer with the resistivity of the listed materials in the question, this resistivity matches that of Copper the most.

Hence, the material is Copper.

Option A is correct. Copper.

Explanation:

Given,

I = 30.0 A

d = 0.326 cm = 0.00326 m

E = 0.062 V/m

The current density for the wire is given as

J = (I/A)

where J = current density = ?

I = current = 30.0 A

A = Cross sectional Area of the wire = (πd²/4) = [π×(0.00326²)/4] = 0.0000083503 m²

J = (30 ÷ 0.0000083503) = 3,592,685.3 A/m²

On a microscopic scale, Ohm's law can be stated as

E = Jρ

where E = Electric field = 0.062 V

J = Current density = 3,592,685.3 A/m²

ρ = Resistivity of the material = ?

ρ = (E/J)

ρ = 0.062 ÷ 3,592,685.3 = (1.726 × 10⁻⁸) Ωm

Comparing this answer with the resistivity of the listed materials in the question, this resistivity matches that of Copper the most.

Hence, the material is Copper.

Hope this Helps!!!

Answer from: GracieMaeB

Complete question:

To learn to apply the concept of current density and microscopic Ohm's law.

A "gauge 8" jumper cable has a diameter of 0.326 centimeters. The cable carries a current of 30.0 amperes. The electric field in the cable is 0.062 newtons per coulomb.

What is the material of the cable?

A. Copper

B. Silver

C. Aluminum

D. Gold

E. Steel

It is made of Copper

Explanation:

We are given:

•diameter d= 0.0326cm = 0.00326m

• Current I = 30A

• Electric field e = 0.062v/m

To find the material of cable, we'll need to find the resistivity of the material using the formula:

R = e/J

We already know e = 0.062v/m

To find current density J, we have:

$J = \frac{I}{pi * r^2}$

But r = d/2 = 0.00326 / 2 = 0.00163

$= \frac{30}{pi * 0.00163 m^2} = 3.594 x 10^6 A/m^2$

Hence resistivity will be,

R = e/J =

$R = \frac{0.062}{3.594*10^6 A/m^2}$

R = 1.725*10^-^8 ohms/m

From the resistivity of the material we can conclude that it is made of Copper

Answer from: Quest

b would be the answer

Answer from: Quest

Your answer is 1.5 hope i

Another question on Physics

Physics, 21.06.2019 14:40

An implanted pacemaker supplies the heart with 72 pulses per minute, each pulse providing 6.0 v for 0.65 ms. the resistance of the heart muscle between the pacemaker’s electrodes is 550 ω. find (a) the current that flows during a pulse, (b) the energy delivered in one pulse, and (c) the average power supplied by the pacemaker.

Answers: 3

Answer

Physics, 21.06.2019 23:30

In which of the following cases is work being done on an object? question 2 options: pulling a trailer up a hill carrying a box down a corridor suspending a heavy weight with a strong chain pushing against a locked door

Answers: 2

Answer

Physics, 22.06.2019 17:30

Aball thrown by ginger is moving upward through the air. diagram a shows a box with a downward arrow. diagram b shows a box with an upward arrow. diagram c shows a box with a downward and upward arrow equal in size. diagram d shows a box with a downward and upward arrow with the downward arrow larger in size. which force diagram represents the forces on the ball? you may neglect the effects of air resistance.

Answers: 3

Answer

Physics, 22.06.2019 23:00

Two horses begin at rest. after a few seconds, horse a is traveling with a velocity of 10 m/s west, while horse b is traveling with a velocity of 13 m/s west. which horse had a greater acceleration? a. horse a because its change in velocity was greater than horse b's in the same time. b. horse b because its change in velocity was greater than horse a's in the same time. c. horse b because its change in velocity was the same as horse a's, but it took less time. d. both horses had the same acceleration.

Answers: 1

Answer

You know the right answer?

To learn to apply the concept of current density and microscopic Ohm's law. A "gauge 8" jumper cable...

Questions