A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground.
Calculate the velocity of the acorn just before it reaches the ground (rounding your answer to the integer) and its kinetic energy when hitting the ground (rounding your answer to the nearest tenth).

Velocity m/s

Kinetic Energy J

Velocity= 19.05 m/s

Kinetic energy= 3.08 J

Explanation:

The corn possess potential energy. Feom law of conservation of energy, all the potential eneegy will be converted to kinetic energy, with negligible friction.

Potential energy, PE= kinetic energy, KE

Potential energy is given by mgh while kinetic energy is given by

Equating

Making v the subject of the formula then

Substituting 9.81 m/s2 for g and 18.5 m for h then the velocity will be

To get the kinetic eneegy, since PE=KE AND KE is

Substituting v with 19.05 and m with 0.017 kg we have

This can also be achieved by mgh since PE=KE hence 0.17*9.81*18.5=3.085245 J and the results are slightly different due to small energy losses and rounding off of values.

the answer would be 32*f

there are no contact forces mentioned on the list of choices that you've provided.