In an ionic solution, a current consists of Ca2+Ca2+ ions (of charge +2e+2e) and Cl−Cl− ions (of charge −e−e) traveling in opposite directions. Part A If 5.02×1018 Cl−Cl− ions go from A to B every 0.620 minmin , while 3.25×1018 Ca2+Ca2+ ions move from B to A, what is the current (in mAmA) through this solution? Part B In which direction (from A to B or from B to A) is the current in part A going?

A

The current through the solution is  

B

The current is moving from B to A

Explanation:

From the question we are told that

      The number of   that move from A to B is

      The time taken to move from A to B  

Since the value of 1 charge is  

The quantity of charge Q that flow from A to B is mathematically given as

   The number of   that move from A to B is

      Since time taken to move from A to B is equal to time taken to move from B to A  

The quantity of charge Q that flow from B to A is mathematically given as

The total quantity of charge is

The current flowing through the solution is

The flow is from B to A cause current  flow from the positive terminal to negative terminal

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

the answer would be c. motion and direction

i hope this : )