Two parallel plates, each having area a = 3557 cm2 are connected to the terminals of a battery of voltage vb = 6 v as shown. the plates are separated by a distance d = 0.59 cm. the battery is now disconnected from the plates and the separation of the plates is doubled ( = 1.18 cm). what is the energy stored in this new capacitor?

U = 4.80 nJ

Explanation:

Given:-

- The area of two parallel plates, A = 3557 cm^2

- The battery has the p.d, Vb = 6 V

- The initial separation of plates, di = 0.59 cm

Find:-

he battery is now disconnected from the plates and the separation of the plates is doubled ( = 1.18 cm).

What is the energy stored (U) in this new capacitor?

Solution:-

- The two parallel plates connected across a potential difference ( battery ) is considered as a capacitor with capacitance (C). The capacitance (C) can with (air in between) be calculated by the following formula:

                                  C = ε*A / d

Where,             ε : Permittivity of free space = 8.84 * 10^-12

- Solve for capacitance (C):

                                 C = (8.84 * 10^-12)*( 0.3557 ) / (0.0059)

                                 C = 5.32947 * 10^-10 F

- The energy stored by the capacitor (U) can be calculated from the following formula:

                                 U = 0.5*C*V^2

                                 U = 0.5*(5.32947 * 10^-10)*(6)^2

                                U = 9.59305 nJ

- When the plates are separated by double the initial distance we see that:

                                 C ∝ 1 / d

When,                        d = 2*di

                                 C = 0.5*C

- Also,

                                  U ∝ C

Hence,                       C = 0.5 C

                                  U = 0.5 U

So, The half of original energy stored calculated above is:

                                  U = 0.5*9.59305 nJ

                                  U = 4.80 nJ

gans

explanation:

vestigial organs (like your appendix) are organs that no longer serve a purpose.

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles