The hydrogen atom consists of a proton of mass 1.67x10-27 kg and an orbiting electron of mass 9.11x10-31 kg. In one of its orbits, the electron is 5.3x10-11 m from the proton. What is the mutual attractive gravitational force between the electron and the proton?

The mass of the proton,
m
p
=
9.11
×
10
−
31
k
g
The mass of the electron,
m
e
=
1.67
×
10
−
27
k
g
The distance between them,
r
=
5.3
×
10
−
11
m

The gravitational force between two objects of mass,
m
1
, and
m
2
, separated by a distance,
r
, is given by the following equation:

F
=
G
m
1
m
2
r
2

Here,

G
=
6.67
×
10
−
11
m
3
/
k
g
.
s
2
is the gravitational constant.
On plugging the given values, we have:

F
=
6.67
×
10
−
11
×
1.67
×
10
−
27
×
9.11
×
10
−
31
(
5.3
×
10
−
11
)
2
=
3.61
×
10
−
47
N

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !