A race car driver is driving his car at a constant speed of 45.0 m/s on a circular track with a radius of 285 m. (a) What is the angular speed (in rad/s) of the car? rad/s (b) What are the magnitude (in m/s2) and direction of the car's acceleration? magnitude m/s2 direction

A) Angular velocity = 0.1579 rad/s

B) Acceleration = 7.11 m/s² in a direction towards the centre of the circle motion

Explanation:

In circular motion,

linear speed = angular speed x radius of the rotation

Thus,

v = ωr

Where;

v = linear speed (m/s)

ω = angular speed (radians/s)

r = radius of the rotation (m)

We are looking for angular speed, thus ;making ω the subject, we have;

ω = v/r

We are given that v= 45 m/s and r = 285m

Thus,

ω = 45/285 = 0.1579 rad/s

B) The formula for Centripetal acceleration is given as;

a_c is given by the expression

a_c = rω² = v²/r

where;

v is linear velocity of the object,

ω is its angular velocity and

r is the radius of the circle in which object moves.

Thus,

a_c = v²/r = 45²/285 = 7.11 m/s²

The centripetal acceleration affects the direction of the car. So in this case the direction of the car will be towards the centre of the circle motion.

learn it on the intertant so you can solve

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .