Physics, 30.03.2020 23:14 cupcakesmc619

Ou whirl a stone in a horizontal circle in such a way that the stone is in uniform circular motion. Which of the following is true for this situation? (Select all that apply.) The magnitude of the stone's velocity does not change. The direction of the stone's velocity changes as it moves around the circle. The stone's speed is constant. The change in direction of the stone's motion is due to the centripetal force acting on the stone. The stone is moving with constant velocity. Incorrect: Your answer is incorrect.

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Answer from: ravenmcfarlandp07okx

The magnitude of the stone's velocity does not change.

The direction of the stone's velocity changes as it moves around the circle.

The stone's speed is constant.

The change in direction of the stone's motion is due to the centripetal force acting on the stone.

The uniform motion of the stone around circular curve is directed inwards due to the centripetal force acting on the stone, keeping the stone moving in the circular path without falling off.

$F = ma_c\\\\F = \frac{mv^2}{r}$

where;

is the centripetal acceleration v is the velocity of the stoner is the radius of the circular path

From the formula given above we can conclude that;

The magnitude of the stone's velocity does not changeThe direction of the stone's velocity changes as it moves around the circle.The stone's speed is constant.The change in direction of the stone's motion is due to the centripetal force acting on the stone.

Learn more about circular motion here: link

Answer from: obalzano6817

The magnitude of the stone's velocity does not change.

The direction of the stone's velocity changes as it moves around the circle.

The stone's speed is constant.

The change in direction of the stone's motion is due to the centripetal force acting on the stone.

Explanation:

When a stone moves along a circular path, the magnitude of its velocity remains the same but the direction of this velocity changes. The direction of the velocity at any point is the tangent to the circular path at that point. The speed of the stone at any point along the circular path is constant since speed is a scalar quantity.

Centripetal force is the force that keeps the stone moving along its circular path.

The velocity of this stone changes even though the magnitude of velocity does not change. The velocity is said to change because its direction changes.

Answer from: Quest

The car would move to the right with 150 n of force. the 150 n of force from friction and air resistance slows the car from moving to the right with 300 n of force.

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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