The weight of an object varies inversely with the second power of the distance from the center of Earth. The radius of Earth is approximately 4000 miles. If a person weighs 160 pounds on Earth's surface, what would this individual weigh 8000 miles above the surface of Earth?

17.8 pounds.

Explanation:

The radius of the Earth is 4000 mi.

now, a person right in the surface of the earth is located at a distance 4000 miles of the center, and we have that the weight will be something like:

W = 160 pounds = A/(4000)^2 pounds

where A is a constant that we do not know, but we can find the value:

A = 160*(4000)^2

Now, at a distance of 8000 miles to the surface we have:

W = A/(4000 + 8000)^2 = 160*(4000)^2/(12000)^2 = 17.8 pounds.

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~