At the point of fission, a nucleus of 235U that has 92 protons is divided into two smaller spheres, each of which has 46 protons and a radius of 5.83 ✕ 10-15 m. What is the magnitude of the repulsive force pushing these two spheres apart?

3581.93928018 N

Explanation:

Number of protons = 46

r = Radius =

q = Charge = 46e

e = Charge of electron =

k = Coulomb constant =

From Coulomb's law

The magnitude of the repulsive force pushing these two spheres apart is 3581.93928018 N

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2