Two students are simultaneously pushing a glider on a frictionless air track, each with a constant horizontal force. In the examples that follow, assume that student 1 always does positive work on the block (Ws, > 0 and that student 2 always does negative work (Ws2 0 Suppose that the glider moves to the left with constant speed. 1. In which direction is each student pushing the block? Use the definition of work to answer

The student 1 pushes to the left, the student 2 pushed to the right

Explanation:

Mechanical Work

The work done by a force F on an object moving a distance X and making an angle with the force is given by

If the force and the distance point in the same direction, the angle is 0 and the work is positive.

If the force and the distance point in opposite directions, the angle is 180° and the work is negative.

We know the glider moves to the left and the student 1 always does positive work, thus he must be pushing the block to the left to have the same direction.

The same can be applied to the second student who does a negative work when the block goes to the left, so he must be pushing to the right direction.

Summary: The student 1 pushes to the left, the student 2 pushed to the right

explanation:

wheres the pic

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j