A 1-m3 tank containing air at 25 °C and 500 kPa is connected through a valve to another tank containing 5 kg of air at 35 °C and 200 kPa. Now the valve is opened, and the entire system is allowed to reach thermal equilibrium with the surroundings, which are at 20 °C. Determine the volume of the second tank and the final equilibrium pressure of air.

Volume of the second tank is 3.21m³

Final eguilibrium presssure is 284.13kpa

Explanation:

Volume of the tank A,

Temperature of air in tank A,

Pressure of air in tank A, P_A = 500kPa

Mass of air in tank B, m_b = 5kg

Temperature of air in tank B,

Pressure of air in tank B,

Surrounding temperature,

Assuming, at given conditions air behaves as an ideal gas.

For air, gas constant R = 0.287 kJ/kmol K

From ideal gas equation, mass of air in tank A is determined by

Volume of the tank B can be determined from

so,when the valve is opened

Total volume,

Volume of the second tank is 3.21m³

Total mass of air,

The final equilibrium pressure (P) can be obtained from the ideal gas equation applied to total volume

Final eguilibrium presssure is 284.13kpa

answer; equivalent to a one(1) horsepower motor;

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this