Physics, 30.03.2020 17:16 genyjoannerubiera

For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The largest vacuum chamber you can find is 60 cm in diameter. Part A What magnetic field strength will you need?

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Answer from: puppy4151

The magnetic field strength, B is 1.043 T.

Explanation:

The expression for the magnetic field is as follows as;

$B=\frac{mv}{qr}$

Here, m is the mass, r is the radius, v is the speed, q is the charge and B is the magnetic field.

According to the given problem, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The largest vacuum chamber you can find is 60 cm in diameter.

v= 10% of the speed of the light

$v=\frac{10}{100}\times3\times10^{8}ms^{-1}$

$v=3\times10^{7}ms^{-1}$

$r=\frac{Diameter}{2}$

$r=\frac{60}{2} cm$

r=0.30 m

Calculate the magnetic field strength.

$B=\frac{mv}{qr}$

Put $v=3\times10^{7}ms^{-1}$ , $m=1.67\times10^{-27}ms^{-1} kg$ , $q=1.6\times10^{-19}C$ and r=0.30 m.

$B=\frac{(1.67\times10^{-27})(3\times10^{7})}{(1.6\times10^{-19})(0.30)}$

B= 1.043 T

Therefore, the magnetic field strength is 1.043 T.

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

Answer from: Quest

Answerinternal combustion engine fuel;

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