A wire that is 1.50 m long and carrying a current of 10.0 A is at right angles to a uniform magnetic field. The force acting on the wire is 0.70 N. What is the strength of the magnetic field?

0.047 T

Explanation:

When a current-carrying wire is placed in a region with a magnetic field, the wire experiences a force, given by the equation

where

I is the current in the wire

L is the length of the wire

B is the strength of the magnetic field

is the angle between the direction of B and I

In this problem:

L = 1.50 m is the length of the wire

I = 10.0 A is the current in the wire

F = 0.70 N is the force exerted on the wire

since the current is at right angle with the field

Solving for B, we find the strength of the magnetic field:

like poles repel so keep pushing north to north and repels funny to see this

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle