When an object with a height of 0.10 meter is placed at a distance of 0.20 meter from a convex spherical mirror, the image will appear to be 0.06 meter behind the mirror. What’s the height of the image?

0.03 m

Explanation:

Mirrors work on the principle of reflection.

Reflection occurs when a ray of light hits a surface and bounces back into the origina medium at a different angle.

We can solve this problem by using the magnification equation:

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

y = 0.10 m is the height of the object

p = 0.20 m is the distance of the object from the mirror

q = -0.06 m is the distance of the image from the mirror (negative because it appears behind the mirror, so it is a virtual image)

Solving for y', we find the size of the image:

And the positive sign indicates that the image is upright.

carla slowed down in the beginning of her trip, stopped, and then sped up

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach