If the ball leaves the projectile launcher at a speed of 2.2 m/s at an angle of 30ᴼ, and the projectile launcher is on a table at a height of 1.1 m, how far horizontally will it hit the ground?

1.12 m

Explanation:

This situation is related to parabolic motion, hence we can use the following equations:

(1)

(2)

Where:

is the ball final height (when it hits the ground)

is the ball initial height

is the initial velocity

is the angle at which the ball was launched

is the time

is the acceleration due gravity

is the horizontal distance the ball travels

Rewriting (1) with the given values:

(3)

Multiplying all the eqquation by -1 and rearranging:

(4)

So, since we have a quadratic equation here (in the form of,  we will use the quadratic formula to find  :  

  (5)

Where , ,  

Substituting the known values and choosing the positive result of the equation, we have:  

(6)

Now, substituting (6) in (2):

(7)

(8) This is the horizontal distance at which the ball hits the ground.

answer; equivalent to a one(1) horsepower motor;

your answer is, orbit around the nucleus