The circuit on the right resonates at 10,000 rad/s with a Q-factor of 10. (a) (3 pts) Determine the values of capacitor C. (b) (3 pts) Determine bandwidth B. (c) (4 pts) Determine resistor R. (d) (3 pts) When the source operates at the resonant frequency, the circuit becomes (A) a purely resistive circuit (B) a capacitive circuit (C) an inductive circuit (D) either an inductive or a capacitive circuit. (Choose one) (e) (3 pts) Find the average power dissipated by the circuit when the source operates at the resonant frequency.

a) C=0.5 uF

b) B=1000 rad/s

c) R= 4kΩ

d) a purely resistive circuit

e) The average power dissipated by the circuit is 25 mW

Explanation:

a) The resonance frequency is:

Clearing C:

b) The bandwidth is:

c)

Clearing R1:

Clearing R:

R= 4kΩ

d) The admittance is:

at resonance 1, then

The impedance is:

Then this is purely resistive, if the source operates at a resonant frequency, the circuit is transformed into a purely resistive circuit.

e) The average power dissipated is equal to:

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.