What average net force is required to accelerate a 9.5 g
bullet from rest to 650 m/s over a distance of 0.85 m along the
barrel of a rifle?

2361 Newtons

Explanation:

From the second Newton's law of motion;

F = ma

In this case;

we are given;

Mass as 9.5 g

Initial speed as 0 m/s

Final velocity as 650 m/s

Distance is 0.85 m

Using the equation;

V² = U² + 2as

But u = 0

v² = 2as

Therefore;

a = v² ÷ 2s

  = 650² ÷ 2(0.85)

  = 248,529.40 m/s²

But;

F = ma

   = 0.0095 kg × 248,529.40 m/s²

   = 2361 Newtons

Therefore;

The average net force required to accelerate the bullet is 2361 Newtons.

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

. west