Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19 C and Coulomb’s constant is 8.987 × 109 N · m2/C2. Answer in units of m.

The distance between the charges is 13.86 X 10⁴m

Explanation:

Given:

Force, F = 1.2N

Charge, q₁ = 1.602 X 10⁻¹⁹ C

k = 8.987 X 10⁹ Nm²/C²

Distance, d = ?

According to Coulomb's law:

Substituting the value in the formula we get:

Therefore, the distance between the charges is 13.86 X 10⁴m

i belive it is d. both a and c

hope this

mark me branliest, only got   it 1

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