Physics, 27.03.2020 06:00 cnicole71

Two toy cars (m1 = 0.200 kg and m2 = 0.250 kg) are held together rear to rear with a compressed spring between them. When they are released, the cars are free to roll away from the ends of the spring.
If you measure the acceleration of the 0.200-kg car to be 2.65 m/s2 to the right, what is the acceleration of the other car?

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Answer from: jeff2852

Acceleration of the second particle at that moment is given as

a_2 = 2.12 m/s^2

Explanation:

As we know that both cars are connected by same spring

So on this system of two cars there is no external force

So we will have

F = 0 = m_1a_1 + m_2a_2

now we have

m_1 = 0.200 kg

m_2 = 0.250 kg

a_1 = 2.65 m/s^2

now we have

0.200(2.65) + 0.250a_2 = 0

so we have

a_2 = 2.12 m/s^2

Answer from: Quest

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Answer from: Quest

another example of kinetic energy would be,

kinetic energy > moving energy

answer > letter choice (c), a hammer falling off a table.

hope that ! : )

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