A string is wrapped around a uniform disk of mass M and radius R. Attached to
the disk are four low-mass rods of radius b, each with a small mass m at the end. The apparatus is initially at rest. With your hand you pull the string straight up with some constant force F and while your hand is moving up a distance L, the apparatus moves downward a distance h with an angular speed ω. At this instant, determine the change in translational kinetic energy in terms of
relevant variables provided in the problem statement and g (acceleration due to gravity).

Change in translational KE is given as

Explanation:

As we know by work energy theorem that work done by all forces is equal to the change in kinetic energy of the system

So here we know that there are two forces acting on the system

So work done by the system of this force is equal to the change in kinetic energy

So we have

So we have

so we have

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s