Another type of mass spectrometer accelerates ions through an accelerator and then through a velocity selector before entering the spectrometer. If the perpendicular magnetic and electric fields in the velocity selector are given by B and E, and the magnetic field in the spectrometer is given by B', derive an expression for the mass of a particle of charge q and radius of curvature R, in terms of B, B', E, q, and R.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

One answer could be erosion