A 3.00 × 10^−9-coulomb test charge is placed near

a negatively charged metal sphere. The sphere

exerts an electrostatic force of magnitude

6.00 × 10^−5 newton on the test charge. What is

the magnitude and direction of the electric field

strength at this location?

(1) 2.00 × 10^4 N/C directed away from the

sphere

(2) 2.00 × 10^4 N/C directed toward the sphere

(3) 5.00 × 10^−5 N/C directed away from the

sphere

(4) 5.00 × 10^−5 N/C directed toward the sphere

(2)  2.0×10⁴ N/C directed towards the  sphere

Explanation:

Electric Field: This can be defined as the force per unit charge. The S.I unit of Electric Field is N/C.

The expression for electric Field is given as,

E = F/q Equation 1

Where E = Electric Field, F = Force, q = charge.

Given: F = 6.0×10⁻⁵  N, q = 3×10⁻⁹ C

Substitute into equation equation 1

E = 6.0×10⁻⁵/(3×10⁻⁹)

E = 2.0×10⁴ N/C directed towards the  sphere

Hence the right option is  (2)  2.0×10⁴ N/C directed towards the  sphere

that would be because of both gravity and friction. so     c

this would be about 43%