A string is stretched to a length of 339 cm and both ends are fixed. If the density of the string is 0.0073 g/cm, and its tension is 859 N, what is the fundamental frequency?

160 Hz.

Explanation:

For nth harmonic, the fundamental frequency,

Here T is the tension in string, \mu is the mass/unit of length of the string and L is the string length.

Given n = 1  frequency of the 1st harmonic (the Fundamental), T = 859 N,

L= 339 cm =3.39 m and .

Substituting these values, we get

Thus, the fundamental frequency is 160 Hz.

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