Two 5.0-g aluminum foil balls hang from 1.0-m-long threads that are suspended from the same point at the top. The charge on each ball is 5.0 * 10-6 C. Find the force that one ball exerts on the other.

F=0.075N

Explanation:

T*cos(θ) = mg=0.005X9.8

T*cos(θ)=0.049N

T = 0.049/cosθ

F = k*q1*q2 / r2

F = 8.9875 * 10^9 * q1*q2 / r^2 q1

F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2

F=0.2246875/r^2

r= 2Lsinθ = 2 x 1 x sinθ =2sinθ

Kindly check the attached for further solution

1/0.14nm = 10^10/1.4 a lot