How many grams of zinc will be formed if 32.0 g of copper reacts with zinc nitrate? Copper(I)nitrate is the other product.

Cu + Zn(NO3)2 → Zn + Cu(NO3)

16.38g of Zn

Explanation:

We'll begin by balancing the equation. This is illustrated below:

2Cu + Zn(NO3)2 → Zn + 2Cu(NO3)

Molar Mass of Cu = 63.5g/mol

Mass of Cu from the balanced equation = 2 x 63.5 = 127g

Molar Mass of Zn = 65g

From the equation above,

127g of Cu produced 65g of Zn.

Therefore, 32g of Cu will produce = (32x65)/127 = 16.38g of Zn.

Therefore, 16.38g of Zn are produced

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