At a certain instant of time a particle with charge q = 15 μC is located at x = 2.0 m, y = 5.0 m; its velocity at that time is v = 40 m/s . If you are at the origin, what do you measure as the magnitude of the magnetic field due to this moving point charge?

2.7 PT

Explanation:

Given that;

Charge (q) = 15 μC =

Velocity (V) = - 40 m/s

Position vector = 2 m î + 5 m î

Magnitude of the position vector |r| = = 5.385

Angle Cos θ =

=

Cos θ = - 0.3714

θ = Cos ⁻¹ (0.3714)

θ = 111.80°

Magnitude field (B) at the origin

B =

B =  

B =

B = 2.7 PT

the answer to your question is high voltage and high currency

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.