The electric field in a certain region of Earth's atmosphere is directed vertically down. At an altitude of 241 m the field has magnitude 46.8 N/C; at an altitude of 93.9 m, the magnitude is 114 N/C. Find the net amount of charge contained in a cube 147.1 m on edge, with horizontal faces at altitudes of 93.9 m and 241 m.

Explanation:

We shall apply Gauss's Law to find the solution .

flux entering the cube = E X A

= 46.8 X 147.1 X 147.1 Weber

flux going out of cube

= 114 x  147.1 X 147.1  Weber

Net flux going out

= ( 114 x  147.1 X 147.1  - 46.8 X 147.1 X 147.1 )

= 1454101.15 weber .

according to Gauss's law

q / ε₀ = 1.4541 x 10⁶ , q is required charge inside the cube.

q = 8.85 x 10⁻¹² x 1.4541 x 10⁶

= 12.868 x 10⁻⁶ C

= 12.868 μC.

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.