A cowboy at a dude ranch fills a horse trough that is 1.53 m long, 61 cm wide, and 42 cm deep. He uses a 2.0 cm diameter hose from which water emerges at 1.25 m/s. How long does it take him to fill the trough? Caution: 2.0 cm is the diameter of the hose, not the radius.

Length of the trough is

l

=

1.5

m

The breadth of the trough is

w

=

60

c

m

Height of the trough is

h

=

40

c

m

The volume of the trough is

V

=

l

×

b

×

h

V

=

(

1.5

)

×

(

0.6

)

×

(

0.4

)

V

=

0.36

m

3

The diameter of the hose pipe is

A

=

π

d

2

4

A

=

(

π

)

(

0.02

2

4

)

A

=

3.14

×

10

−

4

m

2

Now for the rate of flow:

Q

=

A

×

V

Q

=

(

3.14

×

10

−

4

)

×

(

0.36

)

Q

=

1.13

×

10

−

4

m

3

Now for the time:

t

=

V

Q

t

=

0.36

1.13

×

10

−

4

t

=

3185.8

s

Thus, the time taken in order to fill the tank is 3185.8 s

Explanation:

this is the answer

small = small current large mag large current