A horizontal force of magnitude 41.1 N pushes a block of mass 4.18 kg across a floor where the coefficient of kinetic friction is 0.594. (a) How much work is done by that applied force on the block-floor system when the block slides through a displacement of 4.85 m across the floor

Explanation:

Given:

Force, f = 41.1 N

Mass = 4.18 kg

Coefficient of kinetic friction, Uk = 0.594

Displacement, x = 4.85 m

Workdone, E = force × distance, x

= 41.1 × 4.85

= 199.335 J

= 0.2 kJ.

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