Projectile Motion—A tennis ball is thrown out a window 28 m above the ground at an initial velocity of 15.0 m/s and 20.0° below the horizontal. How far does the ball move horizontally before it hits the ground?

The horizontal distance the ball traveled is required.

The distance the ball moved horizontally is 27.1 m.

y = Displacement in y direction = 28 m

u = Initial velocity = 15 m/s

= Angle =

= g = Acceleration in y direction =

t = Time

Displacement in y direction is given by

The time taken to reach the ground is 1.92 s

Displacement in x direction

The distance the ball moved horizontally is 27.1 m.

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The distance will be x = 41.7 [m]

Explanation:

We must first find the components in the x & y axes of the initial velocity.

The acceleration is the gravity acceleration therefore.

g = 9.81 [m/s^2]

Now we can calculate how long it takes to fall.

With this time we can find the horizontal distance that runs the projectile.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

this means that the temperature of both substances will be equal