Given two identical 2.2 kg masses. The first mass is moving with a velocityFind the kinetic energy of the compound system immediately after the collision. Answer in units of J. v1 immediately before colliding with the second mass, which is suspended by a string of length 0.82 m . The two masses are stuck together as a result of the collision. The compound system then swings to the right and rises to the horizontal level. The acceleration of gravity is 9.8 m/s 2

where is the initial velocity of the moving block

Explanation:

We can apply the law of momentum conservation to calculate the compund velocity post-collision:

where are the masses of block 1 (the moving block) and block 2. are the initial velocities before collision of block 1 and 2, and as it's at rest initially.

So the kinetic energy right after the collision is

To calculate the horizontal level where the compound rises to, we need to apply the law energy conservation. As the compound rises its kinetic energy is converted to potential energy:

where m is the mass and h is the vertical distance traveled, v is the velocity at the bottom, and g = 9.8 m/s2 is the gravitational acceleration.We can divide both sides by m:

second mirror gathers light from a faraway object and reflects it to another mirror. - a.

i think the answer would be b