If a pitcher throws a 120 m/s fastball how much force does he need to apply if he is in contact with the ball for 1.5 seconds

Force on the fast ball is given as

here m = mass of the ball

Explanation:

As we know that initially fast ball is moving with speed 120 m/s

now after force applied to the ball it comes to rest

So final speed of the ball is ZERO

now time interval of applied force is

t = 1.5 s

now we have

Now as per Newton's II law we know

here m = mass of the ball

i need the answer to this too but idk it ; -;

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

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