Marvin uses a long copper wire with resistivity 1.68 x 10^-8 Ω⋅m and diameter 1.00 x 10^−3 m to create a solenoid that has a 3.00 cm radius.

Part A: Calculate the total resistance if Marvin uses 11.3 meters of wire to create the solenoid.

Part B: Calculate how many turns are in the solenoid.

Part C: A 3.00 Volt potential difference is applied across the wires of the solenoid. Calculate the current that passes through the solenoid.

Part D: If the coils in the solenoid are separated so that they are evenly spaced across a total length of 0.1 m, what is the magnitude of the magnetic field along the central axis inside of the solenoid?

Answer with Explanation:

We are given that

Resistivity of copper wire=

Diameter=d=

Radius of copper wire=

Radius of solenoid=r'

1 m=100 cm

a.Length of wire=l=11.3 m

Area of wire=A=

Where

A=

Resistance, R=

Using the formula

B.Length of solenoid= m

Number of turns=

=60

C.Potential difference,V=3 V

Current,I=

I=

D.Total length =0.1 m

Number of turns per unit length,n=

Magnetic field along central axis inside of the solenoid,B=

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.