A gymnast of mass mb suspends himself on the rings with his body upright and straight arms that are horizontal with which he clutches the rings. Each ring is suspended by a rope with tension T that makes an acute angle d with his arms, and the rings are separated by a distance d.

a. Solve for the T and d. Assume symmetry.

b. If the gymnast weighs 600 N, d = 75 degrees, and d = 1.8 m, find T

a.

b. 310.58 N on each rope

Explanation:

a. Since the system is symmetrical, tension forces on both ropes are the same. So the T (tension) force can be split in to 2 components: the horizontal forces (of the 2 ropes) are equal and opposite to each other and thus cancel out themselves. The vertical forces are in the opposite direction with the gymnast gravity and equal in magnitude

The vertical component is

Where d here is the acute angle between the rope and the horizontal arms.

The distance d between the rings are the total arm lengths of the gymnast

b.

it is called kinetic energy

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards