If a ball is thrown in the air with a velocity 44 ft/s, its height in feet t seconds later is given by y = 44t − 16t2.. (a) find the average velocity for the time period beginning when t = 2 and lasting . (i) 0.5 second.. ft/s. (ii) 0.1 second.. ft/s. (iii) 0.05 second.. ft/s. (iv) 0.01 second.. ft/s

SO the velocity of the ball while it is thrown in the air is 44ft/s its height per feet T seconds later is give by y = 44t-16t^2, the time peroid of the initial velocity is 2 seconds so find the following:
A. 0.5 seconds after is increased by 18ft/s^2
B. 0.1 seconds after is increased by 0.94ft/s^2
C.0.05 seconds after is increased by 0.18ft/s^2
D. 0.01 seconds after is increased by 0.094ft/s^2