A 1.85-m3 rigid tank initially contains air whose density is 1.18 kg/m3. The tank is connected to a high-pressure supply line through a valve. The valve is opened, and air is allowed to enter the tank until the density in the tank rises to 5.30 kg/m3. Determine the mass of air that has entered the tank.

we can conclude that mass of air that has entered the tank is 7.80 kg.

Explanation:

given data

volume = 1.85 m³

density 1 = 1.18 kg/m³

density 2 = 5.30 kg/m³

solution

we know that density is the mass present in per unit volume so that is

mass = density ×  volume    1

here density is change so put here value in equation 1 we get

mass = (  5.30 - 1.18 ) kg/m³  × 1.85 m³  

solve it we get

mass = 7.807 kg

so we can conclude that mass of air that has entered the tank is 7.80 kg.

7.622 kg

Explanation:

Volume, V = 1.85 m³

initial density of air, d = 1.18 kg/m³

final density of air, d' = 5.3 kg/m³

initial mass of air, m = volume x initial density

m = 1.85 x 1.18 = 2.183 kg

final mass, m' = volume x final density

m' = 1.85 x 5.3 = 9.805 kg

mass of air entered, m' - m = 9.805 - 2.183 = 7.622 kg

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j