The angular speed of an automobile engine is increased at a constant rate from 1260 rev/min to 3460 rev/min in 9.90 s. (a) What is its angular acceleration in revolutions per minute-squared

13333.33 rev/min²

Explanation:

Given:

Initial angular speed of the automobile (ω₁) = 1260 rev/min

Final angular speed of the automobile (ω₂) = 3460 rev/min

Time interval for the change in speed (t) = 9.90 s

Angular acceleration of the automobile (α) = ?

Consider the sense of rotation to be positive. So, making use of the equation of motion of rotation, we have:

Rewriting in terms of 'α', we get:

Converting time 't' from seconds to minutes using conversion factor.

1 sec =

So, 9.90 s =

Plug in all the given values and solve for 'α'. This gives,

Therefore, the angular acceleration in revolutions per minute squared is 13333.33 rev/min².

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