In principle, the motion of a simple pendulum and an object on an ideal spring can both be used to provide the basic time interval or period used in a clock. Which of the two kinds of clocks becomes more inaccurate when carried to the top of a high mountain?

Simple-pendulum clock

Explanation:

A simple pendulum clock is defined as a clock that is comprised of a fixed mass, that is hanged at one end, which is commonly known as the pivot with the help of a string that is comprised of a definite length. This pendulum is then allowed to swing back and forth by simply displacing it at a certain angle and thereby releasing it. This results in the periodic motion.

The time period of this type of clock directly depends on its rate of acceleration under the influence of gravitational force. Due to this, it is considered to be an inaccurate clock when used at the top of high mountains.

cant without the picture! ?

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer